tag:blogger.com,1999:blog-8283950071005526162.post3502225685637935705..comments2023-12-09T13:25:54.553+01:00Comments on Para's Puzzle Site: Puzzle #140: Broken SudokuParahttp://www.blogger.com/profile/02367804879917808922noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-8283950071005526162.post-62754932707262224792012-11-22T02:06:56.561+01:002012-11-22T02:06:56.561+01:00I'm going to go ahead and make a sweeping stat...I'm going to go ahead and make a sweeping statement, and say that, ignoring rotation, reflection and square order,there are 12 solutions. Assuming I reduced symmetries properly that is.<br /><br />All solvable subsets require the use of FILPTUVY, though there doesn't appear to be one which resolves uniquely, unless you're willing to additionally ignore the I pentomino, and only consider the remaining 5*4 rectangle.<br /><br />Oh, and 66 possible piece combinations isn't particularly terrifying (though certainly far more than I'd like to manually check for the sake of a comment).termhttp://meanderlawn.blogspot.com/noreply@blogger.comtag:blogger.com,1999:blog-8283950071005526162.post-69893651462875918602012-11-20T21:23:54.547+01:002012-11-20T21:23:54.547+01:00That's okay. Pentomino packing has always been...That's okay. Pentomino packing has always been a really weak thing for me. I think that's why I like pentomino genres where you pack them through other clues (like sum or A-E) as I'm then able to do it much easier.Parahttps://www.blogger.com/profile/02367804879917808922noreply@blogger.comtag:blogger.com,1999:blog-8283950071005526162.post-548553097990762592012-11-20T20:51:36.128+01:002012-11-20T20:51:36.128+01:00Much as I hate to be annoying, but after a little ...Much as I hate to be annoying, but after a little doodling I have an example of two 5x5 squares tiled by 10 different pentominoes. Up to various symmetries, I'm fairly sure it's a unique solution for this set of 10. Sadly 12 choose 10 is quite a big number so I'm not going to make any sweeping statements.<br /><br />Maybe I should refrain from giving any more details immediately in case you want to find this (or maybe another!) solution yourself!Tom Collyerhttps://www.blogger.com/profile/03663579809785456634noreply@blogger.com