Wednesday 4 October 2017

WSC Practice #3: Round 6 - Puzzle 1: Incremental Arrow Sudoku

This is the third practice puzzle for the 2017 WSC.

Obviously some of the puzzles are going to come from the 6th round as it has new types. I figured I might as well start at the beginning of the round. This also seemed like a type that would suit my writing style.
The overall design idea was to make a long arrow and match the givens in the same place. I think it worked out well. The other 2 matching arrows just add a little bit extra to the aesthetics. This is probably the easiest puzzle out of the three practice puzzles so far. It's really a matter of making one single opening deduction and the rest of the puzzle flows pretty easily.

Rules for Sudoku

In this Sudoku, there are a number of arrows. Starting from the third digit on the arrow, each digit is the unit's digit of the sum of the previous two digits on the arrow.

4 comments:

  1. ..16:11..Really good practice sudoku.Got a nice idea of how this sudoku works.Do you solve this variant by eliminating possibilities until you get that one digit which works,even if you find that earlier or do you go along a digit if it doesn't contradict without surely checking if the other possibilities contradict.I go by the former and for that reason I feel that this variant is too workmanlike somewhat on the lines of kropki.

    ReplyDelete
    Replies
    1. The set up here was that there can't be 3 or more consecutive cells on an arrow that are odd. There is only one place for an even digit in the three cells in the middle nonet. From there it's not too much work to figure out the whole arrow.
      Solving depends a lot on the puzzle. Sometimes you have to start with the arrows, other times the arrows will come later. Here you get a bit of both. It's not necessarily workman like if you find the right place to start.

      Delete
  2. Thanks.I really enjoy solving your practice sudokus.

    ReplyDelete
  3. Great creation.
    10.24 for this.I got the start easily from the fact that sum of two odd nos can't be odd,just as you posted earlier.Thanks :)

    ReplyDelete